Which of these four log expressions is the smallest?
Question
Which is the smallest of these values?
- log10π,
- log10(π2),
- (log10π1)3,
- log10π1.
Suggestion
Can we rewrite the expressions using the laws of logs and indices? Is the substitution L=log10π helpful to us?
Solution
Let L=log10π. Since π<10, we have L<1. Then
- log10π=L;
- log10(π2)=2log10π=2L>L×L=L;
- (log10π1)3=L−3>1;
- log10π1=21log10π1=L2>2.
So the smallest value is L, and the answer is (a).