Which is the largest of the following four numbers?
log23,
log48,
log32,
log510.
Suggestion
Can we evaluate any of the logarithms exactly?
What do we know about logab when 0<b<a?
Solution
Useful fact; if 0<b<a then logab<1, since b<a1.
Firstly, we notice that log32<1, while the other logarithms are greater than one, so (c) cannot be the answer.
Secondly, we might want to calculate some of the logarithms.
Useful fact; suppose we know logs to base j and want to know logs to base k.
Then if logkx=y, we have x=ky, and taking logs to base j,logjx=ylogjk, so y=logkx=logjklogjx .
Since both 4 and 8 are powers of 2, log48 can be easily calculated. log48=log24log28=23
At this point we will compare log23 and log510 with 23.
The ⟺ symbol is really useful. A⟺B means that A is true if, and only if, B is true. Another way to say this is that A implies B, and B implies A; A and B are always true together, or false together.
We start by supposing log23>23 and follow through the logical implications to see if it is true. log23>23⟺2log23>3⟺log29>3⟺9>23, which is true. Therefore, log23>log48. Similarly, log510<23⟺log5100<3⟺100<53, which is true. Hence, log510<log48. From the results above, we can conclude that the biggest number is log23, so the answer is (a).
Alternatively, we could argue we know the biggest is either log23=x, or log510=y.
So 2x=3, and since 22=2(1.414...)<3, x>1.5.
But 5y=10, so 5y−1=2, and since 5>2,y−1<0.5, so y<1.5. So x is the biggest.