Ionic Half Equations (Cambridge International IGCSE Science)
Spec point —
C4.1.8· Construct ionic half-equations for reactions at the anode (to show oxidation) and at the cathode (to show reduction)
Ionic half equations
Extended tier only
-
Electrochemistry is concerned with the transfer of electrons
- This is why the definitions of oxidation and reduction are in terms of losing or gaining electrons, not oxygen
- Oxidation is the loss of electrons
- Reduction is the gain of electrons
-
As the ions come into contact with the electrode:
- Electrons are lost or gained
- The ions form neutral s ubstances
- These substances are discharged as products at the electrodes
-
At the anode, negatively charged ions lose electrons
- So, oxidation occurs at the anode
-
At the cathode, the positively charged ions gain electrons
- So, reduction occurs at the cathode
-
Ionic half-equations only show half of what is happening in a reaction involving electron transfer
- The ionic half-equation for oxidation shows the loss of electrons
- The ionic half-equation for reduction shows the gain of electrons
-
Ionic half-equations must have the atoms and charges balanced
Writing ionic half-equations
Metals
-
Metals are positive ions, e.g. Li+, Cu2+, Al3+
-
If a metal is produced during electrolysis:
- The metal ions will gain electrons to form metal atoms
- The metal ions will be reduced
-
The charge on the metal ion indicates the number of electrons that will be gained
- For example:
Li++ e–→ Li
Cu2++ 2e–→ Cu
Al3++ 3e–→ Al
Non-metals
-
Non-metals are typically negative ions, e.g. Cl–, Br–, OH–
- The hydrogen ion, H+, is an exception to this
Hydrogen ion / hydrogen half-equation:
-
If hydrogen is formed during electrolysis:
- Two hydrogen ions will gain 2 electrons to form hydrogen, H2
- Hydrogen ions are reduced
2H++ 2e–→ H2
Halide ion / halogen half-equation:
-
If a halogen is formed during electrolysis:
- Two halide ions will lose 2 electrons to form the halogen
- Halide ions are oxidised
2X–→ X2+ 2e–
Hydroxide ion / oxygen half-equation:
-
The ionic half-equation for hydroixde ions forming oxygen is more challenging to balance
- Hydroxide ions lose electrons to form oxygen, O2, and water, H2O
- Hydroxide ions are oxidised
4OH–→ O2+ 2H2O + 4e–
Table of reduction and oxidation reactions at the electrodes
| Electrolysis of | Anode reaction | Cathode reaction |
|---|---|---|
| Molten lead(II) bromide, PbBr2 | 2Br– → Br2 + 2e– | Pb2+ + 2e– → Pb |
| Concentrated aqueous sodium chloride, NaCl | 2Cl– → Cl2 + 2e– | 2H+ + 2e– → H2 |
| Dilute sulfuric acid, H2SO4 | 4OH– → O2 + 2H2O + 4e– | 2H+ + 2e– → H2 |
Exam Hint
To help you remember the definitions of oxidation and reduction, use OIL RIG
- Oxidation Is Loss (of electrons) Reduction Is Gain (of electrons)
To help you remember where oxidation and reduction take place, use a RED CAT and AN OX
- REDuction at the CAThode
- ANode for OXidation
Was this revision note helpful?
Build on this topic